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3 years ago

Find the 15th term in the following arithmetic sequence : 1, 6, 11, 16,

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

This arithmetic sequence starts at 1 and increases by 5 every time. The formula for this sequence could be expressed as A(n) = 1 + 5(n-1).

Since you're finding the 15th term, substitute n = 15 into the formula.

A(15) = 1 + 5((15)-1) = 1 + 5(14) = 1 + 70 = 71

Nataly [62]3 years ago

4 0

Answer: 71

Step-by-step explanation:

Every time the number in the sequence increases, it adds 5.

1. 1

2. 1+5=6

3. 6+5=11

4. 11+5=16

5. 16+5=21

6. 21+5=26

7. 26+5=31

8. 31+5=36

9. 36+5=41

10. 41+5=46

11. 46+5=51

12. 51+5=56

13. 56+5=61

14. 61+5=66

15. 66+5=<em><u>71</u></em>

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Andreyy89

Answer:

Segment AD is 3, and segment AE is 2.

Step-by-step explanation:

In a triangle, the line joining the mid points of two sides is parallel and half of the third sides of the triangle.

Here, ABC is a triangle,

In which,

AB = 6,

AC = 4,

D∈ AB and E∈AC

Let DE ║BC,

And, $DE=\frac{1}{2}BC$

In triangles ADE and ABC,

$\angle ADE\cong \angle ABC$ ( Alternative interior angle theorem )

$\angle AED\cong \angle ACB$

By AA similarity postulate,

$\triangle ADE\sim \triangle ABC$

∵ Corresponding sides of similar triangle are in same proportion,

$\implies \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{BC}{2BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{2}$

$\implies AD = \frac{AB}{2}\text{ and }AE =\frac{AC}{2}$

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Hence, the correct option would be,

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