X > 4
Suppose that x is some number so 6 times a number is 6*x. 20 more than that number is 20 + x. If you put it together the inequality would be 6x > 20 + x. Subtracting x from both sides would result in 5x > 20. Dividing by 5 gives you x > 4 which is the final answer. So the possible values of that number is anything greater than 4.
Answer:
Ok but what is this for
Step-by-step explanation:
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Answer:
x^2+y^ 2+2x-4y-11=0
x^2 + 2x + ? +y^2 - 4y + $ = 11 + ? + $
x^2 + 2x + 1 + y^2 - 4y + 4 = 11 + 1 + 4
(x + 1)^2 + (y - 2)^2 = 16
(x - - 1)^2 + (y - 2)^2 = 4^2
Center (-1,2) and radius = 4 (see bold in line above)
Step-by-step explanation:
