Answer:
308[cos(45) + isin(45)]
Step-by-step explanation:
z1×z2:
Modulus: r1 × r2
= 7×44 = 308
Argument: theta1 + theta2
= -70 + 115 = 45
z1z2 = 308[cos(45) + isin(45)]
Or
z1z2 = 154sqrt(2) + (i)154sqrt(2)
sqrt: square root
Answer:

Step-by-step explanation:
So we have the expression:

And we wish to factor it.
First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

This is a technique called quadratic u-substitution. Now, we can factor in this form.
We can use the numbers -3 and -2. So:

For the first two terms, factor out a u.
For the last two terms, factor out a -3. So:

Grouping:

Now, substitute back the x² for u:

And this is the simplest form.
And we're done!
Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
Y= |x+1|-2
———— is the answer hope that helps
x
Standard Form: 702.656
Expanded Form: 700+2+0.6+0.05+0.006