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VikaD [51]
3 years ago
13

HELP NEEDED!

Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0

Answer:

10000\pi

Step-by-step explanation:

The formula for circumference is given by 2\pi r. Setting this equal to the circumference in the problem, we can find the radius of the sphere:

2\pi r=100\pi, \\r=\frac{100\pi}{2\pi},\\r=50

Now we can use the formula for the surface area of a sphere:

Surface area of a sphere: A=4\pi r^2

Using r=50:

A=4\cdot \pi \cdot 50^2,\\A=4\cdot 2500\cdot \pi,\\A=\boxed{10000\pi}

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Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
Who knows the answer to this ?
Iteru [2.4K]

Answer:

D

Step-by-step explanation:

6 0
2 years ago
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If y= 17 inches , x= 19 inches , and h=9 inches , what is the area of the object ?
mr Goodwill [35]

Step-by-step explanation:

brainly.com/question/12448502

7 0
2 years ago
I’ll give brainliest please help! Explain the Polynomial equation using Long division
erastova [34]

Answer:

The solution is in the image

4 0
2 years ago
What is 14=9-x I am trying to solve it
prisoha [69]
14 = 9 - x

First, subtract 9 from both sides.

14 - 9 = (9 - 9) - x
5 = -x

Now divide both sides by -1.
5/-1 = -1/-1x
-5 = x

The answer is x = -5.
6 0
3 years ago
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