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3 years ago

15% I paid to buy a computer.39150 dollars I have at all.How much is the computer cost?

Mathematics

2 answers:

rosijanka [135]3 years ago

8 0

You would’ve paid $5,872.50 for the computer

LenKa [72]3 years ago

5 0

Answer:

the answer is 58,712.5

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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago

Suppose a candy connoisseur opened a random bag of candy and found that 15 of the 62 candies were red. Using this information, d

Yakvenalex [24]

Answer: E= 0.107

Step-by-step explanation:

Formula to find the margin of error : $E=z^*\sqrt{\dfrac{p(1-p)}{n}}$

, where n= sample size .

p= sample proportion

z* = critical value.

Given : Sample size : n= 62

Number of red candies out of 62 = 15

Proportion of red candies = $p=\dfrac{15}{62}\approx0.242$

We know that , the critical value for 95% confidence = z*= 1.96 [Using z-table]

Then,

$E=(1.96)\sqrt{\dfrac{0.242(1-0.242)}{62}}$

$E=(1.96)\sqrt{\dfrac{0.242(0.758)}{62}}$

$E=(1.96)\sqrt{\dfrac{0.183436}{62}}$

$E=(1.96)\sqrt{0.00295864516129}$

$E=(1.96)(0.0543934293945)$

$E=0.106611121613\approx0.107$

Hence, the margin of error = E= 0.107

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3 years ago

Find the sum of r + s, when r= -14.1 and s = 18.3

Vladimir79 [104]

The answer is 4.2 because you have to replace r with -14.1 and s with 18.3. After that you subtract them and you get 4.2

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