Answer:
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
Step-by-step explanation:
Step 1
Express the angle of inclination as follows;
Tan∅=H/R
where;
∅=angle of inclination
H=vertical rise
R=distance of run
Step 2
Determine the angle inclination when;
H=3 feet
R=2 feet
replacing;
Tan∅=(3/2)=1.5
∅=Tan^(-1)(1.5)
∅=56.31°
Determine the angle inclination when;
H=5 feet
R=3 feet
replacing;
Tan∅=(5/3)=1.67
∅=Tan^(-1)(1.67)
∅=59.03°
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
For a vertical projectile, the equation of motion is expressed h(t)=g+bt+c, where g is gravity, b is the initial upward velocity, and c is the starting height. The maxima of this equation is given by -b/2g, which in this case would be -56/-32, or 1.75 seconds after launch
☺☺☺☺
Answer:
Each of the other cats have 45 whiskers on average.
Step-by-step explanation:
Let x represent the average number of whisker of each cat.
We have been given that there are 7 cats in my neighborhood, with an average of 41 whiskers each.
The total number of whiskers of six cats would be 
.
Since one of the cats has 17 whiskers, so the total number of whiskers of 7 cats would be 
We will use average formula to solve our given problem.
Upon substituting our given values, we will get:
Let us solve for x.
Switch sides:
Therefore, the each of the other cats have 45 whiskers on average.
42/48 in simplest form is 7/8
