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sertanlavr [38]
3 years ago
12

22. Determine the value of c so that the line

Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

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Step-by-step explanation:

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Find all the zeros of <br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7B6x%7D%5E%7B4%7D%20%20%20-%20%20%7B7x%7D%5E%7B
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Step-by-step explanation:

I find a graphing calculator to be a most useful tool for problems like this. (See attached.)

_____

First of all, observe that the constant is -2, so 0 is not a zero.

It is often useful to look at the sum of coefficients. Here, that is 0, indicating 1 is a zero.

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5 0
2 years ago
Solve the equation for y. 8x – 9y = 11
Vikentia [17]
8x - 9y = 11    (subtract 8x from each side)

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y = \frac{-8}{-9} x - \frac{11}{9}

D. y=\frac{8}{9} x - \frac{11}{9}


6 0
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