Your numbers are 11 and 32
We know that:
a + b = 44
and
a = 3b
If we substitute “3b” in for a in the first equation, we get a numerical value for b
3b + b = 44
4b = 44
b = 11
Then we substitute the numerical value of b to solve for a:
a = 3b
a = 3(11) = 33
Answer:
A. Z = 2 + N13
Step-by-step explanation:
Let's solve your equation step-by-step.
0=z2+4z−9
Step 1: Subtract z^2+4z-9 from both sides.
0−(z2+4z−9)=z2+4z−9−(z2+4z−9)
−z2−4z+9=0
For this equation: a=-1, b=-4, c=9
−1z2+−4z+9=0
Step 2: Use quadratic formula with a=-1, b=-4, c=9.
z=
−b±√b2−4ac
2a
z=
−(−4)±√(−4)2−4(−1)(9)
2(−1)
z=
4±√52
−2
z=−2−√13 or z=−2+√13
Answer:
Step-by-step explanation:
Charlie has $27
He spent $3 for kid's meal for his little brother
Remaining money=27-3=$24
Number of Sandwiches he wants to buy = 6
Money he needs to pay for each sandwich = 24/6 = $4
Answer:
x < 0
Step-by-step explanation:
If you were to graph the function, you would get a parabola that opens down with the vertex at (0, 0). So, the graph is increasing from -∞ to 0.
Answer:
2.
Step-by-step explanation:
The first numbers in the ordered pairs are the x values;
Difference = 1 - 3 = -1
The absolute value is 2.
