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Nikitich [7]
2 years ago
13

A helicopter’s velocity increases from 35 m/s to 70 m/s in 10 seconds. What is the acceleration of this helicopter?

Physics
1 answer:
Alenkinab [10]2 years ago
3 0
3.5 meters per second second is the acceleration because we know that acceleration is change in velocity over time and the change is velocity here is 35 and the time is 10 so we can simply divide 35 by 10 which is 3.5 m/s squared
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On planet X, an object weighs 7.04 N. Onplanet B where the magnitude of the free-fallacceleration is 1.91g(whereg= 9.8 m/s2isthe
timurjin [86]
<h2>Mass of object in Earth is 1.37 kg</h2>

Explanation:

On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.

We have

           Weight = Mass x Acceleration due to gravity

On planet B

           25.74 = Mass x 1.91 g

           25.74 = Mass x 1.91 x 9.81

           Mass = 1.37 kg

Mass is constant for an object. It will not change with location.

Mass of object in Earth = Mass of object in Planet B

Mass of object in Earth = 1.37 kg

4 0
3 years ago
Identify the arrows that show input force
Lesechka [4]
⬆️ I think it’s the one that goes up ( sorry if it’s wrong )
3 0
2 years ago
Read 2 more answers
A pump is used to send water through a hose, the diameter of which is 10 times that of the nozzle through which the water exits.
Keith_Richards [23]

Use VFR1 = VFR2 to discover the velocity at in the hose VFR = A * V

D hose =10 * D nozzle, R hose = 5 * D nozzle

Area of a circle = πR^2

Area h=3.14*25*D^2 = 75.5D^2

(Radius=Diameter/2) area n = 3.14*(D^2/4) = .785D^2

 

Use VFR = VFR v2 = 0.4m/s

0.4*.785D^2 = 75.5*D^2* v1 D^2

= .314 =75.5*V1

v1 = 0.004m/s

 

Now we have the velocity, we can use Bernoulli's equation.

P1+ρgh1+ρV1^2 /2 = constant

There is no atmospheric pressure before so the P1= the gauge pressure at the pump, let’s call the height of the hose 0m and the height of the nozzle 1m so the is no ρgh1 Likewise, there is only atmospheric pressure at the nozzle which is 100000 PA, and lastly the density ρ of water is 1000 KG/M^3

Pg + 1000*.004^2/2 = 100000+1000*9.8*1+ 1000*0.4^2/2

Pg + .008= 100000+9800+80

Pg+.008= 109880

Pg=109880.008 PA

3 0
3 years ago
Which two factors determine the arhount of work done?
Scilla [17]
<h2>Answer:distance and force</h2>

Explanation:

Let W be the work done.

Let F be the force applied.

Let S be the displacement of the object.

Workdone by a object is defined as the dot product of force and displacement.

W=F.S

Since distance is the magnitude of displacement when force and displacement are in a same direction,

|W|=|F|\times distance

So,work done depends on force applied and distance.

8 0
3 years ago
Read 2 more answers
Which of the following instrument would you prefer to measure the length of table
Wittaler [7]

Answer:

4. meter rod​

Explanation:

The length of an object is dimension that expresses how long the object is. It is measured in meters as the SI unit.

From the given question, to determine the length of a given table, the appropriate instrument that should be used is a meter rod. This would make it possible to measure in meters and know the exact dimension of the object with respect to how long it is.

A meter rod has a length of 1 m (100 cm), and can be easily used for the purpose.

8 0
3 years ago
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