1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
torisob [31]
3 years ago
5

At time t = 0, a 2150-kg rocket in outer space fires an engine that exerts an increasing force on it in the +x-direction. This f

orce obeys the equation F = At^2, where t is time,
and has a magnitude of 781.25 N when r = 1.25 s. (a) Find the SI value of the constant A, including its units. (b) What impulse does the engine exert on the rocket during the I .50-s
interval starting 2.00 s after the engine is fired? (c) By how much does the rocket?s velocity change during this interval?
Physics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

a)  A = 500 N/s²

b)  I = 5812.50 N-s

c)  Δv = 2.7034 m/s

Explanation:

Given info

m = 2150 kg

F(t) = At²

F(1.25 s) = 781.25 N

a) A = ?

We use the equation

F(t) = At²  ⇒     781.25 N = A*(1.25 s)²

⇒ A = F(t) / t² = (781.25 N) / (1.25 s)²

⇒ A = 500 N/s²

b) I = ?  if   2.00 s ≤ t ≤ 3.50 s

we apply the equation

I = ∫F(t) dt = ∫At² dt = A ∫t² dt = (500/3)*t³ + C

Since the limits of integration are 2 and 3.5,  we obtain

I = (500/3)*((3.5)³-(2)³) = 5812.50 N-s

c) Δv = ?

we can apply the equation

I = m*Δv   ⇒   Δv = I / m

⇒   Δv = 5812.50 N-s / 2150 kg

⇒   Δv = 2.7034 m/s

You might be interested in
The Nile river excellent for. what
myrzilka [38]
1.) Transportation og goods and people

2.) Farming because of the rich minerls in its rivers

3.) The fertile soil near the river which helpes grow flax, wheat and papyrus.
7 0
3 years ago
Read 2 more answers
12. An example of an atom that has no charge is one that has A. 3 protons, 1 electron, and 3 neutrons. B. 3 protons, 2 electrons
andreyandreev [35.5K]
_____________________________

[D. 2 protons, 2 electrons, and 1 neutron.]

As we know that, protons are embedded in the nucleus with neutron having no charge. So, nucleus has positive charge. Electrons are revolved around the nucleus of the atom. Proton has positive charge and electron has negative charge.

Number of proton = Number of electron.

Hence, both 2 protons and 2 electrons make the atom electrically neutral. So, the net charge of atom is 0. Neutron are the subatomic particle which has only mass.

_____________________________
8 0
3 years ago
calculate the percentage contraction of a rod moving with a velocity of 0.8c in a direction inclined at 60° to its own length​
hram777 [196]

Answer:

Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.

Now length of the rod along the direction of motion

= lo cos 60°_/1-(0.8) 2/c2

= lo/2×0.6

= 0.3 lo.

Length of the rod perpendicular to the direction of motion.

= lo sin 60°

=_/3/2 lo

Length of moving rod

l = [(0.3lo)2+{lo_/3/2} 2] 1/2

= 0.916 lo.

Percentage contraction

= lo-0.916lo/lo×100

= 8.4%.

Explanation:

<h2><u><em>Brainliest?</em></u></h2>
4 0
3 years ago
A 4.88 x 10-6 C charge moves 265 m/s
Alex73 [517]

Answer:

F=0N

Explanation:

From the question we are told that:

Charge Q=4.88 x 10-6 C

Velocity v= 265m/s

Angle \theta =0 \textdegree

Magnetic field B=0.0579T

Generally the equation for Force is mathematically given by

 F=Q(\=v*\=B)

 F=qvBsin\theta

Therefore

 F=qvBsin0 \textdegree

 F=0N

5 0
3 years ago
Read 2 more answers
The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista
SIZIF [17.4K]
I guess the problem is asking for the distance between Earth and Mars in Astronomical Units (AU).

Since 1 AU = 1.5 \cdot 10^8 km
and the distance between the two planets is
d=225 mil. km= 2.25 \cdot 10^8 km
we can convert this distance into AU by using the following proportion:
1 AU : 1.5 \cdot 10^8 km = x : 2.25 \cdot 10^8 km

from which we find
x= \frac{1 AU \cdot 2.25 \cdot 10^8 km}{1.5 \cdot 10^8 km} =1.5 AU
7 0
3 years ago
Read 2 more answers
Other questions:
  • Compared to the volume of earth the volume the sun is approxately?
    10·1 answer
  • As shown in the figure below, Justin walks from the house to his truck on a windy day. He walks 20 m toward
    5·1 answer
  • In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller i
    10·1 answer
  • PLEASE HELP ME A lens with a surface that curves outward like the exterior of a sphere is __________. (Points : 1) reflected ref
    9·2 answers
  • Consider N non-interacting diatomic molecules stuck on a metal surface. Each molecule can either lie flat on the surface, in whi
    5·1 answer
  • Given the indices of refraction n_1 and n_2 of material 1 and material 2, respectively, rank these scenarios on the basis of the
    7·1 answer
  • If the speed of an object is unchanging, then what must be true?
    12·2 answers
  • There are 12 third grade students and 15 4th grade students in the band they will travel to a concert in cars that can hold four
    6·1 answer
  • 2 Pete is driving down 7th street, He drives 150 meters in 18 seconds, Asaimning he does not speed up or
    9·1 answer
  • Where did Rutherford believe the protons were found
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!