Help me out please..........

What is the volume of the sphere that has a diameter of 3? use 3.14 for pie

aev [14]

Hey ! there

Answer:

113.04 unit cube

Step-by-step explanation:

In this question we are provided with a sphere having radius 3 units and value of π is 3.14 . And we're asked to find the volume of sphere .

For finding volume of sphere , we need to know its formula . So ,

$\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} = \dfrac{4}{3} \pi r {}^{3} }}}$

Where ,

π refers to 3.14

r refers to radius of sphere

Solution : -

Now , we are substituting value of π and radius in the formula ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times (3) {}^{3}$

Simplifying it ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times 3 \times 3 \times 3$

Cancelling 3 with 3 :

$\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}} \times 3.14 \times 3 \times 3 \times \cancel{3}$

We get ,

$\quad \longrightarrow \qquad \:4 \times 3.14 \times 9$

Multiplying 4 and 3.14 :

$\quad \longrightarrow \qquad \:12.56 \times 9$

Multiplying 12.56 and 9 :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{113.04 \: unit \: cube}}}} \quad \bigstar$

Henceforth , volume of sphere having radius 3 units is 113 .04 units cube .

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a plumber charges $52.50 per hour plus a $75.00 service charge your father's firm hires him to fix some leaky pipes find the tot

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0.000000452 in scientific notation

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Answer:

4.52 x 10^-7

Step-by-step explanation:

you have a very small number (numbers to right of decimal) so you're exponent will be negative.

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What will your balance be on an investment of $7000 at 2% for 4 years compounded annually.

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Your balance would be 35, I think

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Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x<-36

Oliga [24]

X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality

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3 years ago