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3 years ago

GIVING 20 POINTS NEED HELP

Mathematics

1 answer:

alexandr1967 [171]3 years ago

6 0

Answer:

4 is a BCA def of rectangle

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A gym has yoga classes. Each class has students. If there are classes, write an equation to represent the total number of studen

zzz [600]

Answer:

s = 14c

Step-by-step explanation:

7 0

3 years ago

Y=r + 5x + 4<br> please help!!!!

frez [133]

Your answer would be R=-5x-4+y

6 0

3 years ago

(−8k+1)(−8k+1) standard form

kifflom [539]

Answer:

64k^2 - 16k +1

Step-by-step explanation:

We can rewrite this as

(-8k+1) ^2

We know that (a+b)^2 = a^2 +2ab +b^2

Let a = -8k and b = 1

(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2

=64k^2 - 16k +1

3 0

3 years ago

Read 2 more answers

What's the solution and answer? And explain please

Advocard [28]

The solution is subtract4.7x on both sides. Then you get -2.2x=7.7. Divide 7.7 by -2.2 and you get x= -3.5

7 0

3 years ago

Find the sum of 1 + 3/2 + 9/4 + …, if it exists.

zmey [24]

Answer:

Option (4)

Step-by-step explanation:

Given sequence is,

$1+\frac{3}{2}+\frac{9}{4}..........$

We can rewrite this sequence as,

$1+\frac{3}{2}+(\frac{3}{2})^2.............$

There is a common ratio between the successive term and the previous term,

r = $\frac{\frac{3}{2}}{1}$

r = $\frac{3}{2}$

Therefore, it's a geometric sequence with infinite terms. In other words it's a geometric series.

Since sum of infinite geometric sequence is represented by the formula,

$S_{n}=\frac{a}{1-r}$ , when r < 1

where 'a' = first term of the sequence

r = common ratio

Since common ratio of the given infinite series is greater than 1 which makes the series divergent.

Therefore, sum of infinite terms of a series will be infinite Or the sum is not possible.

Option (4) will be the answer.

3 0

3 years ago