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Ad libitum [116K]
3 years ago
8

GIVING OUT BRAINLIST QUICK!

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

26

Step-by-step explanation:

Use this times this divided by this and wala you have your answer witch is 26.

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Factor the polynomial completely. Use synthetic division. <br><br> F(x) = x^3-7x-6
aleksklad [387]

Answer:

The factors of given polynomial    x =-1 , -2 and x =3

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given the polynomial  

                    f(x) =  x³ - 7x -6

 put x =-1

               f(-1) = (-1 )³- 7(-1) - 6 = -1+7-6=0

(x+1) is a one factor

By using synthetic division

                   x³    x²      x      constant

     x=-1  ↓   1      0      -7        -6

             <u>↓   0     -1      1          6</u>

            <u>       1       -1      -6       0     </u>

<u />

<em>The polynomial    x² - x - 6 </em>

<u><em>Step(ii):-</em></u>

The factors ( x+1)(x² - x - 6 ) = 0

     x = -1 and x² - x - 6 =0

    x =-1    and  x² - 3x + 2 x - 6 =0

   x =-1     and  x (x -3) + 2( x-3) =0

   x =-1     and  (x+2)(x-3) =0

<u><em>Final answer:-</em></u>

The factors of given polynomial    x =-1 , -2 and x =3

6 0
3 years ago
What is the volume of a rectangular prism with the base area of 15m2 and height of 5cm?
koban [17]

Answer:

The correct answer is option C. 75 m³

Step-by-step explanation:

<u>Points to remember</u>

Volume of rectangular prism = Base area * Height

<u>To find the volume of given prism</u>

Here Base area = 15 m² and

Height = 5 m

Volume = base area * height

 = 15 * 5

 = 75 m³

Volume of prism = 75 m³

Therefore the correct answer is option C. 75 m³

3 0
3 years ago
Read 2 more answers
David, Ben, and Jordan shared stickers in a ratio of 8 : 9 : 10. If Ben had 36 stickers, how many stickers did Jordan have?
pantera1 [17]

Answer:

Jordan had 40 stickers.

Step-by-step explanation:

For this ratio, we have David:Ben:Jordan as 8:9:10, and so we need to make it as a more complex fraction, 8/9/10, now we need a multiplier to get us from 9 stickers of Jordan to 36, like a giant one. The common multiplier in this case is 4, and we know that the values must always stay proportional. We multiply everything by 4,and we get a final ratio of 32:36:40, and since Jordan is the last in the ratio David:Ben:Jordan, Jordan ends up with 40 stickers.

3 0
3 years ago
Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
3 years ago
Please help me with this homework question. What's 5+4?
Bogdan [553]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
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