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brilliants [131]
3 years ago
7

Ayo, what's your opinion on blue haired girls?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
7 0
I think it’s cool if they have blue hair
damaskus [11]3 years ago
4 0

If it’s full blue hair nah I don’t like it but if it’s like highlights it’s cool

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What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)
Pepsi [2]

Answer:

Vertical Asymptote:

x=1

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

f(x)=log_3(x-1)

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

x-1=0

we get

x=1

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

\lim_{x \to \infty}  f(x)= \lim_{x \to \infty}log_3(x-1)

\lim_{x \to \infty}  f(x)=log_3(\infty-1)

\lim_{x \to \infty}  f(x)=undefined

so, it does not exist

7 0
3 years ago
Read 2 more answers
What is the probability that a person who is above 35 years old has a hemoglobin level of 9 or above?
amm1812

Answer:

option C

0.531

Step-by-step explanation:

Given in the question,

total number of people of age 35 years = 162

Total number of people of age 35 and having haemoglobin 9 or above

162 - 76

86

probability  = 86/162

                   = 0.531

7 0
2 years ago
Read 2 more answers
Which expression represents the follow-
Varvara68 [4.7K]

Answer:

the sum of x and 5.

x + 5

the sum of is adding

4 0
3 years ago
If a set of sample measurements has a mean of 100, a normal distribution, a standard deviation of 2, and control limits of 94 an
weeeeeb [17]

Answer: 99.73%

Step-by-step explanation:

Given : Mean : \mu=100

Standard deviation : \sigma=2

Let X be the random variable that represents the data values.

Formula for Z-score :  z=\dfrac{X-\mu}{\sigma}

For x=94, we have

z=\dfrac{94-100}{2}=-3

For x=106, we have

z=\dfrac{106-100}{2}=3

The probability that the samples are between 94 and 106:-

P(-3

Hence, the percent of the samples are expected to be between 94 and 106 = 99.73%

6 0
3 years ago
Find a number if 0.7 of it is 3.43.
lukranit [14]
Answer : I’m thinking 2.73 .

It shouldn’t be a trick question just fake 3.43 minus .7!
3 0
2 years ago
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