Sorry im a little late but here's how i did it.
Hope this helps! :)
For this case we have the following vector:
v = (- 8, 2)
Using product point we have:
v.v = (-8, 2). (- 8, 2)
v ^ 2 = (-8) * (- 8) + (2) * (2)
v ^ 2 = 64 + 4
v ^ 2 = 68
v = root (68)
v = root (4 * 17)
v = 2 * root (17)
Answer:
v = 2 * root (17)
option c
Answer:
x + 3y + 9 = 0
Step-by-step explanation:
y=3x + 2
Coefficient of x = 3
Gradient (m) of line y= 3x + 2 is 3
Since the line passing through point
(3,-4) is perpendicular to line y=3x + 2
hence gradient (m) of the line is -1/3;
And hence it equation is given as;
y - y1 = m(x - x1)
y - (-4) = -1/3(x - 3)
multiplying through by 3;
3 × y + 3 × 4 = 3 × -1/3(x - 3)
3y + 12 = -1(x - 3)
3y + 12 = -x + 3
x + 3y + 12 - 3 = 0
x + 3y + 9 = 0
Answer:2/15 hope this helps
Step-by-step explanation:
Answer:
55 minutes
Step-by-step explanation:
