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Answer:
The correct answer is 25% likely.
Explanation:
Phenylketonuria (PKU) is inherited in an <u>autosomal recessive pattern</u>, which means <u>both copies of the gene in each cell must have mutations</u> to express the disease.
If we let the allele causing PKU be “p” and the normal allele be “P”, the affected individual must have “pp” combination. If both parents are heterozygous, this means the have “Pp” combination and therefore the result in their progeny will be the following:
¼: PP (25%)
¼: pp (25%)
½: Pp (50%)
This pattern will repeat itself every time they try to have a child.
Someone with Emphysema will usually be diagnosed with COPD ( Chronic obstructive pulmonary disease) This means their air sacs in there lungs are damaged and the inner walls of the the lungs are weakened and cause larger air spaces. This disease commonly causes bronchitis frequently, hard time breathing , lower immune system.