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Serga [27]
3 years ago
11

Brainliest for whoever gets this correct with working out

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer: 2x-5 / x+5

Step-by-step explanation:

(2x^2 - 3x - 5) / (x^2 + 6x + 5)

Write -3x as a difference

= (2x^2 +2x - 5x -5) / (x^2+5x+x+5)

Factor out 2x from the expression

= 2x *(x+1) -5 * (x+1) / x*(x+5)+x+5

Factor out x+1 from the expression

= (x+1) * (2x-5) / (x+5)* (x+1)

Reduce the fraction with x+1

= 2x-5 / x+5

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5 sevens go into 37 withought going over
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Express the recurring decimal 1.52 as an improper fraction
ElenaW [278]

(152÷4)(100÷4) = 3825 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 152100 is also equal to 11325 when expressed as a mixed number.

5 0
3 years ago
Read 2 more answers
How do I use inductive reasoning to predict the next three numbers in the pattern 9,11,13,15,17
MA_775_DIABLO [31]

You inspect the series that you have, very carefully.

-- You notice that 9 was <em><u>increased by 2</u></em> to get 11.
-- You notice that 11 was <em><u>increased by 2</u></em> to get 13.
-- You notice that 13 was <em><u>increased by 2</u></em> to get 15.
-- You notice that 15 was <em><u>increased by 2</u></em> to get 17.

By now, it begins to dawn on you.  You say to yourself  "Self !  I'll just bet
that each term has to be increased by 2 in order to get the next term."

Acting on that assumption, you set out on your flight of prediction:

-- You take the last term, 17, increase it by 2,and get 19.

-- You take the new term that you have created, 19,
increase it by 2, and get 21.

-- You take the 2nd new term that you have created, 21,
increase it by 2, and get 23.

Now you have the three new terms, and that's all you were asked for.
But you're just getting warmed up.  Nothing can stop you now.

25,  27,  29,  31,  33,  35,  37,  39,  41,  43,  45,  47,  49, 
51,  53,  55,  57,  59,  61,  63,  65,  67,  69,  71,  73,  75, 
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Suddenly, you stop !   You just realized that this is not the ONLY
possible pattern that would produce the same first 5 numbers.


6 0
3 years ago
Read 2 more answers
Using the similar triangles, which equation could be used to find the slope of line AB?
NARA [144]

Answer:

A) slope = p/q

Step-by-step explanation:

Slope of any given can be found using the formula, \frac{rise}{run} = \frac{y_2 - y_1}{x_2 - x_1}.

In this case, using similar triangles, the rise over the run of any of the given similar triangles will give us the slope of line AB.

This means, slope of line AB would be:

\frac{rise}{run} = \frac{m}{n} = \frac{p}{q}.

✅Therefore, slope of line AB = p/q

6 0
3 years ago
A student is trying to solve the system of two equations given below: equation p: y z = 6 equation q: 3y 4z = 1 which of these i
Vadim26 [7]

<u>Option C is correct </u><u>(y + z = 6) ⋅ −3</u>

What is a linear equation in math?

  • A linear equation only has one or two variables.
  • No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
  • When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.

As per the statement -

A student is trying to solve the system of two equations given below:

Equation P:   y + z = 6              ....[1]

Equation Q:  3y + 4z = 1           ....[2]

Multiply the equation [1] by -3 to both sides we have;

-3 .( y + z = 6 ) ⇒ -3y -3z = -18..........(3)

                   

Add equation [2] and [3] to eliminate the y-term;

z = -17

Therefore, the  possible step used in eliminating the y-term is, (y + z = 6) ⋅ −3

Learn more about linear equation

brainly.com/question/11897796

#SPJ4

<u>The complete question is -</u>

A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of these is a possible step used in eliminating the y-term?

(y + z = 6) ⋅ 4

(3y + 4z = 1) ⋅ 4

(y + z = 6) ⋅ −3

(3y + 4z = 1) ⋅ 3

6 0
1 year ago
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