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Studentka2010 [4]
3 years ago
10

Over Fall break, Tory read 5 times as many pages as her brother and sister combined. Tory read 1840 pages and her brother read 2

00 pages. How many pages did her sister read? Write an equation and solve for the number of pages her sister read.
Mathematics
2 answers:
finlep [7]3 years ago
7 0

Answer

368

Step-by-step explanation:

1840÷5=368

Tatiana [17]3 years ago
7 0

Answer:

170,

Step-by-step explanation:

my explanation is commented on the other persons answer

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What is the measure of angle z in this figure?
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Hello!

I've attached a photo for reference.

Lines A and B form straight angles, which  measure 180 degrees. That means that - 

m∠x + m∠y = 180°
m∠y + m∠z = 180°
m∠z + 43° = 180°
43° + m∠x = 180°

Since you're trying to find z, use the solvable equation with z in it:

m∠z + 43° = 180°
180 = z + 43
137 = z

Answer:
m∠z = 137°

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Please help <br><br> f(x)=x^2+x-1<br> g(x)=-3x+12 <br><br> Find g(f(x))
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Step-by-step explanation:

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Name the property of real numbers illustrated by the equation (x + 8) + 4 = x + (8 + 4)
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Step-by-step explanation:

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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

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