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3 years ago

Find the slope of a line that goes through the points (5,-2) and (1,0).

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

Answer:

B(-1/2)

Step-by-step explanation:

So remember, the slope is y2-y1/x2/x1. Note that y2 means the second y adn x2 means the second x.

So lets plug in our numbers for the top of our fraction, y2-y1. This is 0- - 2.

You should get postive 2, since -- equals a + so it would be 0+2 equaling 2.

This is your y value of your slope.

Next lets find the x value of the slope.

Lets plug in our numbers for the bottem raction this time, which is x2-x1. This is 1-5.

You should get negative 4, since 1-5 equals -4.

This is the x value of the slope.

Knowing your y and x value of the slope, we can tell that the slope will be:

2/-4

This can be simplyfied to -1/2. Since 2 goes into 2, 1 time(for y). Then 2 goes into -4, -2 times(for x). So now its 1/-2.

The negative sign can just be moved to the front since it is the only negative and does not change:

Answer:

<u>-1/2</u>

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1) $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$ is simplified into $-9x-11$

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Step-by-step explanation:

We need to solve the polynomials.

1) $(-2x+4)+(x-6)$

Solving:

$(-2x+4)+(x-6)\\=-2x+4+x-6\\Combining\,\,like\,\,terms:\\=-2x+x+4-6\\=-x-2$

So, $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$

Solving:

$(uv-3)+(4uv+1)$

Expanding:

$=uv-3+4uv+1\\Combining\,\,like\,\,terms:\\=uv+4uv-3+1\\=5uv-2\\$

So, $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$

Solving:

$(11x-8)-(2x+3)$

Expanding:

$=11x-8-2x-3\\Combining\,\,like\,\,terms:\,\,\\=11x-2x-8-3\\=-9x-11$

So, $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$

Solving:

$(x^2-4)-(x-2)$

Expanding:

$=x^2-4-x+2\\Combining\,\,like\,\,terms:\\=x^2-x-4+2\\=x^2-x-2$

SO, $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$

Solving:

$(12-3t-7t^2)+(1+3t-t^2)$

Expanding:

$=12-3t-7t^2+1+3t-t^2\\Combining\,\,like\,\,terms:\\=12+1-3t+3t-7t^2-t^2\\=13+0t-8t^2\\=-8t^2+13$

So, $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Keywords: Solving Polynomials

Learn more about solving Polynomials at:

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This question was not written correctly

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Hence, the value of 50 × 50

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