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Sloan [31]
3 years ago
9

Do 5 and 6 and 7/8 yall can do this

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

5) D. Trapezoid.

6) C. Trapezoid.

7) B. All parallelograms are quadrilaterals.

8) A.  A Polygon is a closed figure with. 3 or more curved or straight sides.

<em>Can I please have brainliest?</em>

<em />

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A bage contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at radom. What is p(yellow)
vodomira [7]
Total marbles = 5 + 3 + 2 = 10
Total yellow marbles = 2
P(yellow)  = 2/10 = 1/5

Answer: 1/5
7 0
4 years ago
Evaluate 4 to 3 power
natta225 [31]
Hello,

Here is your answer:

The proper answer to this question is...."64"!

Here is how:

First translate the problem:

4^3=4×4×4=64

Your answer is 64!

If you need anymore help feel free to ask me!

Hope this helps!
3 0
3 years ago
Find the length AB round your answer to the tenth
Kobotan [32]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

AB =  \sqrt{ ({3 - ( - 2)})^{2} +  ({4 - 0})^{2}  }  \\

AB =  \sqrt{ ({3 + 2})^{2} +  {4}^{2}  }

AB =  \sqrt{ {5}^{2} +  {4}^{2}  }

AB = \sqrt{25 + 16}

AB = \sqrt{41}

AB = 6.403

AB = 6.4

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3 0
3 years ago
A mountain bike is priced at $413. If the sales tax is 6.5 percent, what is the cost to purchase the mountain bike? Round to the
mamaluj [8]

Answer: See explanation

Step-by-step explanation:

1. Cost = $413

Sales percent = 6.5%

Cost of bike = $413 + (6.5% × $413)

= $413 + (0.065 × $413)

= $413 + $26.845

= $439.85

2. Cost of dishwasher = $569

Commission rate = 18%

The expression for the commission will be:

= 18% × $569

= 18/100 × $569

= 0.18($569)

8 0
3 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
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