Answer:
4th degree polynomial with leading coefficient of 1.
As x goes to negative or positive infinity, y goes to positive infinity in both cases.
Step-by-step explanation:
The degree of a polynomial is the highest exponent on the variable. Here it is 4.
The leading coefficient is the coefficient on the the term with the highest degree, Here there is none so it is 1.
The end behavior is how x and y behave at negative and positive infinity. When graphed, this equation has a W shape. This means at each end y goes to positive infinity.
Answer:
Step-by-step explanation:
Given
Parabola has x-intercept has
and 
and Y-intercept as 
Now the general equation of parabola is

Substitute
in
we get

Now substitute
in equation 

Now substitute
in equation 

Solving
and
we get

therefore


The value of x from the figure is 1 and the equations that represent angle relationships in the figure are 7x + 5x = 3 + 9 and 12x = 12
<h3>Lines and angles</h3>
The point where two lines meet is known as an angle. From the given diagram;
7x-9 = 5x + 3
Determine the value of x
7x + 5x = 3 + 9
12x = 12
x = 12/12
x = 1
Hence the value of x from the figure is 1 and the equations that represent angle relationships in the figure are 7x + 5x = 3 + 9 and 12x = 12
Learn more on lines and angles here: brainly.com/question/25770607
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Answer:
Step-by-step explanation:
We have volume of cone as

and for a cone always r/h = constant
Given that r' = rate of change of radius = -7 inches/sec
(Negative sign because decresing)
V' =- 948 in^3/sec
Radius = 99 inches and volume = 525 inches
Height at this instant = 
Let us differentiate the volume equation with respect to t using product rule
![V=\frac{1}{3} \pi r^2 h\\V' = \frac{1}{3} \pi[2rhr'+r^2 h']\\-948 = \frac{1}{3} \pi[2(99)(-7)(\frac{0.1607}{\pi})+99^2 h']\\](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2%20h%5C%5CV%27%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%5B2rhr%27%2Br%5E2%20h%27%5D%5C%5C-948%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%5B2%2899%29%28-7%29%28%5Cfrac%7B0.1607%7D%7B%5Cpi%7D%29%2B99%5E2%20h%27%5D%5C%5C)
![-948 = \frac{1}{3} \pi[2(99)(-7)(\frac{0.1607}{\pi})+99^2 h']\\-948 = 33(3.14)(-2.25/3.14 + 99 h')\\-9.149=-0.72+99h'\\-8.429 = 99h'\\h' = 0.08514](https://tex.z-dn.net/?f=-948%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%5B2%2899%29%28-7%29%28%5Cfrac%7B0.1607%7D%7B%5Cpi%7D%29%2B99%5E2%20h%27%5D%5C%5C-948%20%3D%2033%283.14%29%28-2.25%2F3.14%20%20%2B%2099%20h%27%29%5C%5C-9.149%3D-0.72%2B99h%27%5C%5C-8.429%20%3D%2099h%27%5C%5Ch%27%20%3D%200.08514)
Rate of change of height = 0.08514 in/sec
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