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3 years ago

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What is the measure of an exterior angle of a regular hexagon? And what's the formula?

1 answer:

Mekhanik [1.2K]3 years ago

5 0

To find the measure of the exterior angle of a regular polygon, we divide 360 degrees by the number of sides of the polygon. Following the formula we have: 360 degrees / 6 = 60 degrees. The measure of each exterior angle of a regular hexagon is 60 degrees.

I hoped it helps you!

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If the infinite curve y = e−9x, x ≥ 0, is rotated about the x-axis, find the area of the resulting surface.

dusya [7]

We are given with the equation
y = e^-9x with the restriction of x <span>≥ 0
If rotated about the x-axis the area of the resulting surface is
A = </span>π ∫ y² dx
Substituing
A = π ∫ (e^-9x)² dx
A = π ∫ e^-18x dx
The limits are from 0 to positive infinity.

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4 years ago

Use the Well-Ordering Principle to prove that given a > 0, a^n > 0 for every positive integer n

pishuonlain [190]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given value:

$\to x > 0$

$\to S= { n\varepsilon N : x^n \leq 0 } \\\\ s \neq \phi \\\\ \to x^n \leq 0\\$

$\to x^{n-1} x\leq 0\\\\ \to x>0 = x^{n-1} \leq 0 \\\\\to n-1 \varepsilon s \\ \ \ _{where} \ \ n-1 < n \\\\\to s= \phi \\\\\to \hence x^n > 0 \\$

8 0

4 years ago

All you need is in the photo

wariber [46]

Answer:

slope is -1, y intercept is 5

Step-by-step explanation:

slope formula is y1-y2 over x1-x2

plug in formula

u get the slope is -1

4 0

3 years ago

Read 2 more answers

Use the identity below to complete the tasks:

quester [9]

Answer:

$a=[2q^{2}r]$

$b=[3s^{2}t]$

Step-by-step explanation:

we have

$8q^{6}r^{3}+27s^{6}t^{3}$

we know that

$8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}$

$27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}$

therefore

$a=[2q^{2}r]$

$b=[3s^{2}t]$

substitute

$a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])$

7 0

3 years ago

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Multiply<br> (2x + 4)(2x - 4)

lakkis [162]

Answer:

4x^2 -16

Step-by-step explanation:

(2x + 4)(2x - 4)

FOIL

first:2x*2x = 4x^2

outer: -4 *2x = -8x

inner: 4*2x = 8x

last: -4*4 = -16

Add them together

4x^2 -8x+8x =-16

4x^2 -16

8 0

3 years ago

Read 2 more answers