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vlada-n [284]
3 years ago
13

Need help!!!! don't know what I'm doing

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

10,000,010

Step-by-step explanation:

10^7+9+1^3

10^7=10,000,000

1^3=1

9+10,000,000+1=10,000,010

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PLEASEEEE HELP URGENT
kotegsom [21]

Answer:

7.1 cm

Step-by-step explanation:

The diagonal of a cube connects two opposite corners.

You can use the diagonal of a cube in a right triangle in which it is the hypotenuse. The legs of the triangle are a diagonal of a face and an edge.

Let the length of the edge be s.

a^2 + b^2 = c^2

s^2 + 10^2 = (\sqrt{150})^2

s^2 + 100 = 150

s^2 = 50

s = \sqrt{50}

s = 5\sqrt{2}

s = 7.1

Answer: 7.1 cm

7 0
3 years ago
What is true about a rhombus and square?
Genrish500 [490]

Answer:

B. all of these are true

Step-by-step explanation:

The Square is a rhombus because all the sides of a square are equal in length. Even, the diagonals of both square and rhombus are perpendicular to each other and bisect the opposite angles. Therefore, we can say the square is a rhombus.

Hope this helped!!

5 0
3 years ago
Let ​f(x)=x2+3x−10​. Enter the x-intercepts of the quadratic function in the boxes. x = and x =
SIZIF [17.4K]

Answer:

X= 2.

X= -5.

Step-by-step explanation:

Hope it was helpful ;)

3 0
2 years ago
Which table represents a linear function?<br> Please hurry I have to finish this soon!
denis23 [38]

Answer:

C

Step-by-step explanation:

A linear function is the repeating of the same word. Therefore, C would be the correct option. Due to the order 3 9 3 9, this is a linear function. This is just the most logical answer. Please let me know if I am wrong. Sorry if I am :(

6 0
2 years ago
Read 2 more answers
PART 1:
Tju [1.3M]
See the attached figure

A(4,8)  B(0,7)  C(4,3)
<span>the line of reflection is x=5
</span>
the reflection is (x,y)-------------------> (10-x,y)
therefore
A(4,8)-----------------> A1(10-4,8)------> A1(6,8)
B(0,7)-----------------> B1(10-0,7)------> B1(10,7)
C(4,3)-----------------> C1(10-4,3)------> C1(6,3)


4 0
3 years ago
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