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Mars2501 [29]
3 years ago
12

Se valoró una alícuota de 10ml de HCl con NaOH AL 0.0548M de la cual se gastó 17.9ml. La concentración molar del ácido es:

Chemistry
1 answer:
Ymorist [56]3 years ago
7 0

Answer:

se lonh hion ffyuk jlngvn

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Complete the balanced neutralization equation
lbvjy [14]

Answer:

2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O

Explanation:

Let's consider the reaction between acetic acid and strontium hydroxide. This is a neutralization reaction, in which an acid reacts with a base to form salt and water. The unbalanced equation is:

HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O

We have 1 acetate ion to the left and 2 to the right, so we will multiply HC₂H₃O₂(aq) by 2.

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Finally, we multiply water by 2 to get the balanced equation.

2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O

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