Given the options it would be B.
Planets orbit the sun in a elliptical pattern around the sun, rather than in a circle.
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Answer:
5. the scattering of α particles by a metal foil
Explanation:
This is the classical Rutherford's experiment in which he bombarded a thin foil of gold with alpha particles which are positively charged helium nucleus.
He did observed that most of the particles passed through the foil relatively undeflected or if they were deflected it was by a very small angle.
Once in a while the alpha particle rebounded completely. An analogy is the one typically mentioned that it was as if we throw a ball at a piece of paper and it rebounds toward us.
This observations led Rutherford to conclude that the nucleus of the atom is very small positely charged and that the atom is relatively empty with electrons of very small masses. His model is referred as the Plum Pudding model and later Bohr modified it to the planetary model.
Observe the movment of other planets would be your answer
Answer is: 3,4
Chemical reaction: HNO₂ + NaOH → NaNO₂ + H₂O.
c₀(HNO₂) = 1,2 M = 1,2 mol/dm³.
c₀(NaNO₂) = 0,8 M = 0,8 mol/dm³.
V₀(HNO₂) = V₀(NaNO₂) = 1 dm³ = 1 L.
c₀(NaOH) = 0,5 M = 0,5 mol/dm³.
n₀(HNO₂)= 1,2 mol/dm³ · 1 dm³ = 1,2 mol.
n₀(NaNO₂) = 0,8 mol/dm³ · 1 dm³ = 0,8 mol.
V(NaOH) = 400 mL · 0,001 dm³/mL = 0,4 dm³.
n₀(NaOH) = c₀(NaOH) · V₀(NaOH).
n₀(NaOH) = 0,5 mol/dm³ · 0,4 dm³ = 0,2 mol.
n(HNO₂) = 1,2 mol - 0,2 mol = 1 mol.
n(NaNO₂) = 0,8 mol + 0,2 mol = 1 mol.
c(HNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
c(NaNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
pH = pKa + log (c(HNO₂) / c(NaNO₂)).
pH = 3,4 + log (0,714 mol/dm³ / 0,714 mol/dm³) = 3,4.
