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3 years ago

During which two months do both the Northern and Southern Hemispheres receive the same amount of energy from the Sun?

Mathematics

2 answers:

Drupady [299]3 years ago

6 0

Answer: The correct answer is March and September

pls mark brainliest

meriva3 years ago

6 0

Answer:

Answer C

Explanation:

The answer is March and September

Step-by-step explanation:

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Divide.

GalinKa [24]

Answer:

156 19/34

Step-by-step explanation:

5323/34

they are both the same!

Hope this helps, have a great day, and stay safe!!

3 0

3 years ago

Read 2 more answers

Which equation has the same solutions as 4x + x - 5 = 0 ?

Lyrx [107]

5x-5=0
You simplify the left side

4 0

2 years ago

Read 2 more answers

Write the number 110 as a sum of hundreds and tens

Cerrena [4.2K]

All you have to do is 100 plus 10 is 110 plus if you need to understand it better you can use base ten blocks use one hundred block and 1 tens block is the same thing. 100 is in one block and 10 is in one tens block. Hope this helped you ( :

5 0

3 years ago

You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

brilliants [131]

Answer:

Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$

Repplacing the info we got:

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$ And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

7 0

3 years ago

A manager at a shopping mall counts 244 males and n females as they enter the mall. The manager realizes that 25% of all males a

san4es73 [151]

Answer:

Step-by-step explanation:

The manager is not correct in her calculation.

Step-by-step explanation:

There are 244 males and n females who entered the mall as the manager at the shopping mall counts.

If 25% of all males are children, then the number of male children are .

Again, the 25% of all female are children, then the number of female chilfren are .

Therefore, the total number of children will be (60 + 0.25n).

But the manager gives the number of children to be 0.25n + 61 who entered the mall.

So, the manager is not correct in that calculation. (Answer)

5 0

2 years ago