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uranmaximum [27]

3 years ago

11

A movie theater sold 1000 tickets and made 7160 in one night if an adult ticket cost 9 and children's ticket cost 5 how many adu

lt tickets were sold

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

If all adult tickets were sold, it would be 9000The difference between an adult ticket and a child ticket is 4
9000-7160 = 1840
1840/4 = 460 = no. of childs tickets1000 - 460 = 540 = no. of adults tickets

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Factor 64u–40.<br> Write your answer as a product with a whole number greater than 1.

Vlada [557]

Answer: 8(8u-5)

Step-by-step explanation:

Find a number that goes into both 64 and 40 the GCF of both is 8 so 8 goes on the outside of the new factor 8u-5 because if we distribute back we should arrive at the original equation

8(8u-5)

8 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

Carl's cable company charges $55 for monthly service plus $4 for each pay-per-view movie. Teleview cable company charges $110 pe

shusha [124]

Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
= 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.

I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>

8 0

4 years ago

The company charges $5 per sq ft, AND has a minimum charge of 3 sq ft per order (meaning if a customer orders something SMALLER

Sindrei [870]

Answer:

15 dollars

Step-by-step explanation:

12 inches = 1 ft

so 12 inch by 12 inches is 1 ft * 1 ft

1 ft* 1 ft

1 ft^2

This is smaller than 3 ft^2 so they will get charged for 3 ft^2

3 ft^2 = 3 ft^2 * $5 / ft^2 = 15 dollars

6 0

3 years ago

A coral reef grows 0.19m every week. How much does it grow in 6 weeks? Write your answer in millimeters.

kondaur [170]

$0.19 \times 6 = 1.14$
The answer is 1.14 millimeters

6 0

3 years ago

Read 2 more answers