The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:
1. <span>Construct a circle with its center at point H.
2. </span><span>Construct horizontal line l and point H on line l
3. </span>Label
the point of intersection of the circle and line l to the left of point
H, point J, and label the point of intersection of the circle and line l
to the right of point H, point K.<span>
4. Construct
a circle with its center at point J and having radius HJ .
Construct a circle with its center at point K having radius HJ
5. </span><span>Label
the point of intersection of circles H and J that lies above line l,
point M, and the point of their intersection that lies below line l,
point N. Label the point of intersection of circles H and K that lies
above line l, point O, and the point of their intersection that lies
below line l, point P.
6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
10x10x10x10=10^4
10x10x10x10=10,000
6x10^5=6x100000
6x10^5=600000
Answer:
I think the answer would be -5
Step-by-step explanation:
Sorry if its wrong
If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
Learn more about angle here
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