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3 years ago

|7m–56|, if m<8 write without using absolute value

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

56-7m

Step-by-step explanation:

l7m–56l m<8

so lets replace m with something smalller then 8, how about 7

so then it would be...

l 7 * 7 - 56 l=

l 49-56 l = l -7 l

but the absulute value of -7 is 7, so how does this help us? well lets see

56-49= 7 this proves that all we have to do is switch the order giving us the solution 56-7m

hope this helped :)

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Answer:

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Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes =68

$Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}$

$68= \frac{\text{Sum of all lengths}}{7}$

$68 \times 7 =\text{a+b+c+d+e+f+g}$

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We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

$476=x+x+x+84+84+84+4x+14$

$476=7x+266$

$\frac{476-266}{7}=x$

$30=x$

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

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Answer:

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Hello!

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Answer:

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