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3 years ago

Tell whether this equation has no solution, one solution, or infinitely

Mathematics

2 answers:

natali 33 [55]3 years ago

8 0

Answer:

infinitely many solutions

Step-by-step explanation:

Debora [2.8K]3 years ago

5 0

Infinity many solutions

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PLEASE HELP ME WITH THIS

SSSSS [86.1K]

Answer:

Step-by-step explanation:

angles on a straight line are 180 so u do 180 minus 47 gives u 133

5 0

3 years ago

Find the measure of the indicated angle to the nearest degree

sweet-ann [11.9K]

Answer:

Im pretty sure its 45 degrees

Step-by-step explanation:

Its an isosceles triangle so the upper 2 angles are Equal and a triangles angles adds up to 180 degrees, so if we have a 90 degree angle (the square) there's only 90 degrees left, so if you divide the 90 degrees by the remaining 2 Equal angles you get 45.

5 0

2 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Is this a linear function? One person sends an email to 2 people. Those 2 people send it to 4 people, and those 4 send it to 8 p

Mumz [18]

Yes; this is a linear function because you plug in a number and multiply it by two, so the function would be y=2x, which is linear despite the fact that it lacks a b value.

Hope this helps! :)

8 0

3 years ago

Which graphs show continuous data? Select each correct answer.

love history [14]

C

Due to the fact that it is starting from 0 and moving in a steady pattern

5 0

3 years ago

Read 2 more answers