Someone help Please ill give 50 points
1 answer:
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Answer:
BM: <u>y = (2/3) x + 16/3</u> with segment length of 2.77
Step-by-step explanation:
AC formula: m = (6-0)/(0-4) = -3/2
(y-0)/(x-4) = -3/2 y = (-3/2)x + 6 ... (1)
BM slope: BM⊥ AC m = 2/3
BM formula: (y-4) / (x- -2) = (y-4) / (x+2) = 2/3
y-4 = 2/3 x + 4/3
<u>y = (2/3) x + 16/3</u> ... (2) -2≤x≤0.31
intercept of AC and BM (M) from (1) and (2): (-3/2)x + 6 = (2/3) x + 16/3
(13/6) x = 2/3 x = (2/3) / (13/6) = 4/13 ≈ 0.31
y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54
M (4/13 , 72/13) or (0.31 , 5.54)
segment BM = √(4/13 - -2)² + (72/13 - 4)² = √1300/169 = 2.77
Answer:
15 miles
Step-by-step explanation:
Let's say the dock is at the origin on a coordinate plane and each unit is 1 mile. If the boat travels 9 mile due north, that means that we move up from the origin (0, 0) 9 units to point A (0, 9). Now, this boat moves 12 miles due west, so we will go 12 units to the left of (0, 9) to point B (-12, 9). See the attached drawing (sorry for the crudeness).
Notice that this is a right triangle with legs of 9 and 12. That means the distance from the boat to the dock is just the hypotenuse, so use the Pythagorean Theorem: distance =
Thus, the answer is 15 miles.
Hope this helps!
