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2 years ago

7

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2 answers:

Likurg_2 [28]2 years ago

7 0

Answer:

um what?

Step-by-step explanation:

I don't understand this

Elena-2011 [213]2 years ago

4 0

:)

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ALGEBRA 1 ASSIGNMENT QUESTIONS

Nezavi [6.7K]

1. 81 1/2 = 163/2
2. 32 1/5 - 64 1/3 =
483/15 - 965/15 =
-482/15 or -32 2/15
3. 16 1/4 = 65/4
4. 49 1/2 + 27 1/3 =
99/2 + 82/3 =
297/6 + 164/6 =
461/6 or 76 5/6

7 0

3 years ago

Houa has an action figure collection. She keeps some in a display case and the rest on the wall. 82 of her action figures are on

Law Incorporation [45]

Answer:

u just 82 + 59% = 130.38

Step-by-step explanation:

8 0

2 years ago

Quadrilateral ABCD is a rectangle. If the coordinates of A

Neporo4naja [7]

<h3>Answer: A) -2</h3>

==========================================

Explanation:

Let's find the slope of line AB

m = (y2-y1)/(x2-x1)

m = (2-7)/(-6-4)

m = (-5)/(-10)

m = 1/2

The slope of line AB is 1/2

To get the slope of BC, we flip the fraction and the sign to get the perpendicular slope

1/2 becomes -2/1 or simply -2

----------

Slope of AB = 1/2

Slope of BC = -2

Notice how the two perpendicular slopes multiply to -1.

We know they are perpendicular because the four angles of any rectangle are always 90 degrees each.

5 0

2 years ago

Given h()<br> - 4x - 4, solve for a when h(x)<br> -8.

Ilia_Sergeevich [38]

Answer:

28

Step-by-step explanation:

this is a function

if h(x) is -8 you would plug it in for x:

-4(-8) -4 a negative × a negative is a positive

32- 4= 28

7 0

3 years ago

Read 2 more answers

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago