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4 years ago

10

What is the ratio between total bits required for such a cache implementation over the data storage bits?

Computers and Technology

1 answer:

Luda [366]4 years ago

6 0

<span>Answer: [ 128 * (32*8 + 20 + 1) ] / [ 128 * (32*8) ] = 277/256</span>

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