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Serggg [28]
4 years ago
10

What is the ratio between total bits required for such a cache implementation over the data storage bits?

Computers and Technology
1 answer:
Luda [366]4 years ago
6 0
<span>Answer: [ 128 * (32*8 + 20 + 1) ] / [ 128 * (32*8) ] = 277/256</span>
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