1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.



6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)
Quadratic trapezoids have only one pair of parallel sides
Answer:
32600
Step-by-step explanation:
Solve your equation step-by-step.
2s+s+12=132
Simplify both sides of the equation.
2s+s+12=132
Simplify:
3s+12=132
Subtract 12 from both sides.
3s+12−12=132−12
3s=120
Divide both sides by 3.
3s/3 = 120/3
s=40
Answer:which one
Step-by-step explanation: which one 50