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anyanavicka [17]
3 years ago
9

Find the area of the figure shown below. Use 3.14 for at and round your answer to the nearest hundredth.

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0

Answer:

<em>A=38.24</em>

Step-by-step explanation:

<u>Compound Area</u>

The figure shows a shape formed by two shapes: Half a circle and a trapezium.

The circle has a radius of r=5.2/2=2.6 and the trapezium has a height of h=6.5 and bases b1=5.2 and b2=3.3.

The area of half a circle is:

\displaystyle A_c=\frac{\pi r^2}{2}

Using pi = 3.14:

\displaystyle A_c=\frac{3.14\cdot 2.6^2}{2}=10.6132

The area of the trapezium is:

\displaystyle A_t=\frac{b_1+b_2}{2}.h

\displaystyle A_t=\frac{5.2+3.3}{2}\cdot 6.5=27.625

The total area of the figure is:

A=10.6132+27.625=38.2382

Rouning to the nearest hundredth:

A=38.24

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3 years ago
In circle O, RT and SU are diameters.
nataly862011 [7]

In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

Given that:

mArc R V = mArc V U,

Angle S O R = 13 x degrees

Angle T O U = 15 x - 8 degrees

<h3>How to calculate the angle TOU ?</h3>

∠SOR = ∠TOU  (Vertically opposite angles are equal).

Therefore:

13 x = 15x - 8

Subtracting 13x from both sides

13x - 13x = 15x - 8 - 13x

0 = 15x - 13x - 8

2x - 8 = 0

Adding 8 to both sides:

2x - 8 + 8 = 0 + 8

2x = 8

2x/2 = 8/2  

x = 4

∠SOR = 13x

= 13(4)

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∠TOU = 15x - 8

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Let a = mArc R V = mArc V U

Therefore:

mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)

Substituting:

a + a + 52 = 180

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In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

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Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: (hypothenuse)^2=(leg_1)^2+(leg_2)^2. And the main trigonometric ratios are:

sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the  trigonometric ratio: sen Θ

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The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the  trigonometric ratio: tan β. Thus,

sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}

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2 years ago
the length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and wid
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Length = l = 3x
Width = w = 2x
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