Answer is X=2 that will leave her with 2 dollars
According to the calculations made, 410 gumballs will be needed to fill the box.
Since you are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween, and each gumball has a radius of 1/2 in, if the packing density for spheres is 5/8 of the volume will be filled with gumballs while the rest will be air how many gumballs will be needed, to determine this amount the following calculation must be performed:
- (Volume of box x 5/8) / volume of gumballs = Amount of gumballs
- Volume of a sphere = 4/3 x 3.14 x (radius x radius x radius)
- Volume of a gumball = 4/3 x 3.14 x (0.5 x 0.5 x 0.5) = 0.5235 inches
- ((7.3 x 5 x 9.4) x 5/8) / 0.523 = X
- (343.1 x 5/8) / 0.523 = X
- 214.4375 / 0.523 = X
- 410 = X
Therefore, 410 gumballs will be needed to fill the box.
Learn more in brainly.com/question/1578538
You need to find the common primes...
18=2*3*3 and 72=2*2*2*3*3 so they have 2*3*3 in common and
2*3*3=18
So 18 is the greatest common factor.
-3x + 6y + 5 = -7
<u> -5 -5</u>
-3x + 6y = -12
-3x + 3x + 6y = -12 + 3x
<u>6y</u> = <u>-12 + 3x</u>
6 6
y = -2 + 1/2x
-3x + 6(-2 + 1/2x) = -12
-3x - 12 + 3x = -12
-3 + 3x - 12 = -12
0x - 12 = -12
<u> +12 +12</u>
<u>0x</u> = <u>0</u>
0 0
x = 0
-3(0) + 6y = -12
0 + 6y = -12
<u>+0 +0</u>
<u>6y</u> = <u>-12</u>
6 6
y = -2
(x, y) = (0, -2)
