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Katyanochek1 [597]
3 years ago
5

Solve 6( x + 20) = 168

Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0

Answer: X=8

Step-by-step explanation:

168/6=28. x+20=28. 8+20=28.

6(8+20)=168

Lisa [10]3 years ago
7 0

Answer:

x=8

Step-by-step explanation:

distribute the 6

6x+120=168

168-120=48

48/6=8

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Identify any extraneous soloution. See pic above
Wewaii [24]

Answer:

x = 3

Step-by-step explanation:

Given

\sqrt{-x+4} = x - 4 ( square both sides )

- x  4 = (x - 4)² ← expand

- x + 4 = x² - 8x + 16 ( subtract - x + 4 from both sides )

0 = x² - 7x + 12 ← in standard form

0 = (x - 3)(x - 4) ← in factored form

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 4 = 0 ⇒ x = 4

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions

x = 3 : \sqrt{-3+4} = \sqrt{1} = 1

right side = 3 - 4 = - 1

left side ≠ right side ⇒ extraneous solution

x = 4 : \sqrt{-4+4} = 0 and right side = 4 - 4 = 0

left side = right side ⇒ x = 4 is the solution

7 0
3 years ago
What are the x-intercepts of the graph of the function f(x)= x^2+4x-12
levacccp [35]
(2,0)
(-6,0)
I just inserted the equation into a graphing calculator. Kinda lazy tonight :/
7 0
3 years ago
I have to determine the coordinates of the x-intercepts of the parabola. please help I need assistance with this practice proble
Roman55 [17]

The x-intercept of a graph refers to the points where the graph cuts or intersects the x-axis.

These are the x-values when y is equal to zero.

From the graph provided, the values of x when the graph cuts the x-axis are:

\begin{gathered} x=-3 \\ and \\ x=-1 \end{gathered}

Therefore, the coordinates of the x-intercepts are:

(-3,0)\text{ and }(-1,0)

The answer type is "Two points".

4 0
1 year ago
I can't figure out the slope of (-5,1) and (6, 4)​
Nuetrik [128]

Answer:

3/11

Step-by-step explanation:

5 0
3 years ago
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
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