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2 years ago

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A data set is made up of these values. 4, 6, 7, 8, 9, 12, 15 Find the interquartile range. O A. 6 - 4 = 2 O B. 12- 6 = 6 O C. 15

- 4 = 11 O D. 15 - 8 = 7

1 answer:

galina1969 [7]2 years ago

3 0

Answer:

The answer is b

Step-by-step explanation:

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Answer:

i. The ratio of the areas of the two triangles is 5:8.

ii. The area of the larger triangle is 24 in².

Step-by-step explanation:

Let the area of the smaller triangle be represented by $A_{1}$ , and that of the larger triangle by $A_{2}$ .

Area of a triangle = $\frac{1}{2}$ x b x h

Where; b is its base and h the height.

Thus,

a. The ratio of the area of the two triangles is:

$\frac{area of the smaller triangle}{area of the larger triangle}$

Area of smaller triangle = $\frac{1}{2}$ x b x h

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= $\frac{1}{2}$ x 8 x h

= 4h

So that;

Ratio = $\frac{\frac{5}{2}h }{4h}$

= $\frac{5}{8}$

The ratio of the areas of the two triangles is 5:8.

b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;

$\frac{area of the smaller triangle}{area of the larger triangle}$ = $\frac{5}{8}$

$\frac{15}{A_{2} }$ = $\frac{5}{8}$

5 $A_{2}$ = 15 x 8

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Marina86 [1]

Step 1 ) Move all terms right side of the equation.

$\displaystyle\ x^{2} + 6x = -18$

$\displaystyle\ x^{2} + 6x + 18 = -18 + 18$

$\displaystyle\ x^{2} +6x + 18 = 0$

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

$\displaystyle\ x^{2} +6x + 18 = 0$

$\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}$

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Step 3 ) Simplify.

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Since the options only provide one of the answer we found, the answer is...

$\displaystyle\ x = -3 - 3i$

•

•

- <em>Marlon Nunez</em>

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