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3 years ago

Round 716.1079 to the nearest hundredth.

Mathematics

2 answers:

Georgia [21]3 years ago

7 0

Answer:

716.11

Step-by-step explanation:

Round 716.1079 to the nearest hundredth.

Here after the decimal point, 1 is in tenths place

0 is in hundredths place

7 is in thousandths place

9 is in ten thousandths place

Now to round the number to nearest hundredths place, we look at the number in thousandths place.

7 is in thousandths place that is greater than 5. so we add 1 with the number in hundredths place

716.11

Ira Lisetskai [31]3 years ago

4 0

. tenths hundredths

0 is in the hundredths place so look at the 7 it is 5 or greater so round up

716.11

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Step-by-step explanation:

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by sum derivation rule we acquire:

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$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

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substitute back:

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Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

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$g(x) \implies {e}^{2x}$

substitute

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differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

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