Question

If the maximum range of projectile is x. show that the maximum height reached by the same projectile is x/4.

Answer 1

Explanation:

Given that,

The maximum range of a projectile is x.

Maximum range occurs when the angle of projection is 45°. Using formula for maximum range.

$R=\dfrac{v^2}{g}$

According to the question,

$x=\dfrac{v^2}{g}$ ...(1)

Maximum height,

$h=\dfrac{v^2}{2g}$

From equation (1).

$h=\dfrac{x}{2}$

Hence, this is the required solution.