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Leya [2.2K]
3 years ago
7

What natural boundary separated british territory from louisiana?

Computers and Technology
1 answer:
Marat540 [252]3 years ago
4 0
<span>Quebec and British; French and Indian War</span>
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There have not been any changes to instruments or music in the last 50 years. The technology in music is still the same.
aliya0001 [1]

Answer:

False i hope this is rigth

7 0
3 years ago
During her presentation, Marie wanted more freedom to move about the room and interact with her audience. She can use _____.
S_A_V [24]

Answer:

The correct answer is:

"a laser pointer and a remote control"

Explanation:

Let us look at the options one by one.

notes pages and an LCD projector

When she is using these options, she cannot have the freedom to move as she has to operate the projector somehow.

laptop computer and a pointer

In this case she has to operate laptop so movement will be reduced.

<u>A laser pointer and remote control</u> will give her a lot of freedom to move as she can use the remote control to operate the slides and the pointer to point stuff ont the slides.

Hence,

The correct answer is:

"a laser pointer and a remote control"

5 0
3 years ago
The intention of this problem is to analyze a user input word, and display the letter that it starts with (book → B).
yulyashka [42]

Answer:

Here is the C++ program:

#include<iostream>  // to use input output functions

using namespace std;     //to identify objects like cin cout

void StartChar(string str)  {  // function that takes a word string as parameter and returns the first letter of that word in capital

   int i;  

   char c;

   do  //start of do while loop

   {

   for (int i = 0; i < str.length(); i++) {  //iterates through each character of the word str

       if(str.length()>25){  //checks if the length of input word is greater than 25

           cout<<"limit exceeded"; }  //displays this message if a word is more than 25 characters long

      c = str.at(i);   // returns the character at position i

       if (! ( ( c >= 'a' && c <= 'z' ) || ( c >= 'A' && c <= 'Z' ) ) ) {  //checks if the input word is contains characters other than the alphabet

            cout<<str<<" is not a word!"<<endl; break;}  //displays this message if user enters characters other than the alphabet

        if (i == 0) {  //check the first character of the input word

           str[i]=toupper(str[i]);  //converts the first character of the input word to uppercase

           cout<<str<<" starts with letter "<<str[i]<<endl;  }  // prints the letter that the word starts with in capital letter

   }   cout<<"Enter a word: ";  //prompts user to enter a word

      cin>>str;   //reads input word from user

}while(str!="#");   }    //keeps prompting user to enter a word until the user enters #

int main()   //start of the main() function body

{ string str;  //declares a variable to hold a word

cout<<"Enter a word: "; //prompts user to enter a word

cin>>str; //reads input word from user

   StartChar(str); }  //calls function passing the word to it

     

Explanation:

The program prompts the user to enter a word and then calls StartChar(str) method by passing the word to the function.

The function StartChar() takes that word string as argument.

do while loop starts. The for loop inside do while loop iterates through each character of the word string.

First if condition checks if the length of the input word is greater than 25 using length() method which returns the length of the str. For example user inputs "aaaaaaaaaaaaaaaaaaaaaaaaaaa". Then the message limit exceeded is printed on the screen if this if condition evaluates to true.

second if condition checks if the user enters anything except the alphabet character to form a  word. For example user $500. If this condition evaluates to true then the message $500 is not a word! is printed on the screen.

Third if condition checks if the first character of input word, convert that character to capital using toupper() method and prints the first letter of the str word in capital. For example if input word is "Computer" then this prints the message: Computer starts with the letter C in the output screen.

The program keeps prompting the user to enter the word until the user enters a hash # to end the program.

The output of the program is attached.

3 0
3 years ago
En que parte del mall del rio venden tarjetas de google play en cuenca​
JulijaS [17]

chxgfk hcyskvuct auhchovuzq vuvscisv

6 0
3 years ago
Suppose you are given a string containing only the characters ( and ). In this problem, you will write a function to determine w
Whitepunk [10]

Answer:

Code is completed below

Explanation:

Source Code in Java:

class Parenthesis

{

boolean hasBalancedParentheses(String eq) //method to check and return if a set of parenthesis is balanced or not

{

int count=0; //to store count of current unclosed opening brackets

for(int i=0;i<eq.length();i++)

{

if(eq.charAt(i)=='(')

count++;

else if(eq.charAt(i)==')')

count--;

if(count<0) //if count falls below zero, there were more closing brackets than opening brackets till this point

return false;

}

if(count>0) //if count is still more than zero, there were less closing brackets than opening brackets

return false;

return true; //if program reaches this point, it has passed all the tests

}

public static void main(String args[])

{

//testing the function

Parenthesis ob=new Parenthesis();

System.out.println(ob.hasBalancedParentheses("()(()())((())())"));

System.out.println(ob.hasBalancedParentheses(")((()())(()))())"));

}

}

8 0
3 years ago
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