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Nataly [62]
3 years ago
9

Which organisms are examples of decomposers? A. rabbits B. lions C. fungi D. trees

Mathematics
2 answers:
NikAS [45]3 years ago
7 0

Answer:

C. fungi

Step-by-step explanation:

Here only<u> </u><u>Fungi</u> is an example of decomposer.

Rabbits and lions are examples of consumers.

Trees are an example of producers.

The following list defines and provides examples of the feeding (trophic) levels that comprise food webs:

Producer: organism on the food chain that can produce its own energy and nutrients. Examples: grasses, Jackalberry tree, Acacia tree

Primary consumer/herbivore: organism that eats mainly plants. Examples: cows, impalas, warthogs, zebras

Secondary consumer/carnivore: organism that eats meat. Examples: leopard, lion

Omnivore: organism that eats a variety of organisms, including plants, animals, and fungi. Examples: humans, aardvarks

Decomposer/detritivores: organisms that break down dead plant and animal material and waste and release it as energy and nutrients in the ecosystem. Examples: bacteria, fungi, termites

Scavenger: animal that eats dead or rotting animal flesh. Examples: vultures, hyenas

Insectivore: organism that mostly eats insects. Example: Red-billed oxpecker

tester [92]3 years ago
7 0

Answer:

C. Fungi

B. Lions

Step-by-step explanation:

C. fungi are called decomposers because they break down the dead and decaying organic matter into simpler substances such as carbon dioxide, water, simple sugars, and mineral salts and provide the nutrients back to the soil

B. A decomposer is a living thing that gets energy by breaking down dead plants and animals, lions eat other animals to get energy.

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Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
3 years ago
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