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Setler79 [48]
3 years ago
13

-5x+7y=-34 -5x+3y=-6

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

<h2>         x = -3,  y = -7</h2>

Step-by-step explanation:

-5x + 7y = -34     ⇒  -5x = -34  - 7y

    -5x + 3y = -6

-34  - 7y + 3y = -6

-34 - 4y = -6          {add 34 to both sides}

  -4y = 28             {divide both sides by (-4)}

     y = - 7

-5x + 3y = -6

-5x + 3(-7) = -6

-5x - 21 = -6        {add 21 to both sides}

-5x = 15            {divide both sides by (-5)}

  x = -3

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Simplify, state all restrictions.
Kipish [7]

The simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

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Rewrite the expression as products

\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Cancel out the common factors

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1

Express 4x^2 - y^2 as (2x - y)(2x + y)

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Cancel out the common factors

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Take the LCM

\frac{1 - x - y}{x + y}

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Read more about expressions at:

brainly.com/question/723406

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