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faust18 [17]
3 years ago
15

Write an equation in slope-intercept form of the line that passes through (-1,4) and (0,2)

Mathematics
2 answers:
noname [10]3 years ago
6 0

Answer:

y = -2x + 39

Step-by-step explanation:

2 - 4 = -2 (with negative numbers graphs help a lot more)

0 - -1 (since there are two negatives together you change both of the signs to their opposite so they both become positive)

0 + 1 = 1

-2/1 = -2 because a negative divided by a positive is a negative

I found the y-intercept by substituting one of the points into y=mx+b

kirza4 [7]3 years ago
5 0

Answer:

the answer is y= -2x+2

Step-by-step explanation:

I hope it's right

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If csc x = −5, find csc(−x) find the period and horizontal shift
ella [17]

Answer:

\csc (-x) = - \csc x = - ( - 5) = 5

Period is 2π

Horizontal shift = 0

Step-by-step explanation:

We know that \sin (-x) = - \sin x and as \csc x = \frac{1}{\sin x}, so, we can write \csc (-x) = - \csc x

Therefore, the if \csc x = - 5 then \csc (-x) = - \csc x = - ( - 5) = 5 (Answer)

Now, the period of \csc x is 2π, hence the period of \csc (- x) is also 2π.  (Answer)

Again. \csc ( - x) = \csc (-x + 0), hence, the horizontal shift of \csc (- x) is 0. (Answer)

6 0
3 years ago
6+6+75millllllliioooon
Mice21 [21]

Answer:

75,000,012

Step-by-step explanation:

enjoy, i guess

6 0
3 years ago
The fastest that a seahorse can travel is 2640 feet per hour.what is its top speed in miles per hour
miv72 [106K]

Answer:

½ mph

Step-by-step explanation:

1 mi. = 5280 ft.

2640⁄5280 = ½

I am joyous to assist you anytime.

4 0
3 years ago
What is the value of the expression-7 3/4 + 3 1/2
Volgvan

Answer:

45/4 or    11.25   or   11 1/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
enyata [817]

Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

(a+b)^{2} = a^{2} + b^{2} + 2ab

∴ (2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k

Now, we know 4k^{2} and 4k will be even values

∴4k^{2} + 1 + 4k will be odd

hence (2k + 1)^{2} will be odd, which means m^{2} will be odd.

7 0
3 years ago
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