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Harlamova29_29 [7]
3 years ago
11

Describe how math in middle school differs from high school math class?

Mathematics
2 answers:
DaniilM [7]3 years ago
8 0
High school math classes are more advanced than middle school math classes
spin [16.1K]3 years ago
4 0
High school math classes are a higher difficulty level, but most of what you learned in middle school math classes is used. It’s best to remember what you learned because you will end up using it in high school.
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2. The Soccer Club is selling T-shirts and washing cars to raise money for a summer trip. Last week, the club raised $292.50 by
Rudik [331]
15x = 292.50
Divide 15 from both sides
X= 5.85
1 T-shirt = $5.85

45x = 747.50
Divide 45 from both sides
X= 16.61

1 T-shirt = $ 16.61
7 0
3 years ago
Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?
ANEK [815]
From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.

Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is <span>(x, y) → (x + 7, y – 6)</span>.
6 0
3 years ago
Read 2 more answers
In integers what is -11 -6
KatRina [158]

Answer:

-17

Step-by-step explanation:

8 0
4 years ago
the radius of a cylindrical water tank is 6.5ft, and its height is 16ft what is the volume of the tank?​
dimulka [17.4K]

Answer:

Volume of cylindrical tank is 2122.64 cubed feet.

Step-by-step explanation:

It is given that:

Radius of cylindrical tank = 6.5 feet

Height of tank = 16 feet

Volume of tank = πr²h

Putting the values in the formula

Volume = 3.24 * (6.5)² * 16

Volume = 3.14 * 42.45 * 16

Volume = 2122.64 cubed feet.

Therefore,

Volume of cylindrical tank is 2122.64 cubed feet.

4 0
3 years ago
Consider 3 trials, each having the same probability of successes. Let X denote the total number of successes in these trials.
Mariulka [41]

Since each trial has the same probability of success, 

Let, <span><span><span>Xi</span>=1</span></span> if the <span><span>i<span>th</span></span></span> trial is a success (<span>0</span> otherwise). Then, <span><span>X=<span>∑3<span>i=1</span></span><span>Xi</span></span><span>X=<span>∑<span>i=1</span>3</span><span>Xi</span></span></span>, 

and <span><span>E[X]=E[<span>∑3<span>i=1</span></span><span>Xi</span>]=<span>∑3<span>i=1</span></span>E[<span>Xi</span>]=<span>∑3<span>i=1</span></span>p=3p=1.8</span><span>E[X]=E[<span>∑<span>i=1</span>3</span><span>Xi</span>]=<span>∑<span>i=1</span>3</span>E[<span>Xi</span>]=<span>∑<span>i=1</span>3</span>p=3p=1.8</span></span>

So, <span><span>p=0.6</span><span>p=0.6</span></span>, and <span><span>P{X=3}=<span>0.63</span></span><span>P{X=3}=<span>0.63</span></span></span>

I thought what I did was sound, but the textbook says the answer to (a) is <span>0.60.6</span> and (b) is <span>00</span>.

Their reasoning (for (a)) is as follows:

3 0
3 years ago
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