Answer:
Step-by-step explanation:
Refer to attached for points
a) f(-1) = 3 as per graph
b) f(x) = 6
We add horizontal line through point y=6 to find intersections with the graph
Take x-values of those points. The points are x = -3, x = -2, x = 2
Answer:
B)60m^2
Step-by-step explanation:
The area of the rectangle is 40m^2 and the area of the triangle is 20m^2. So 40+20 is 60.
A there are no real zeros
using the discriminant b² - 4ac to determine the nature of the zeros
for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )
• If b² - 4ac > 0 there are 2 real and distinct zeros
• If b² - 4ac = 0 there is a real and equal zero
• If b² - 4ac < 0 there are no real zeros
b² - 4ac = 16 - 20 = - 4
Since discriminant < 0 there are no real zeros
Answer:
There appears to be a difference between the pulse rates from samples of adult males and females. The average pulse rate of males is 63.75 while that of females is 75.875.
Coefficient of Variation (male) = 33.44%
Coefficient of variation (female) = 28.35%
Step-by-step explanation:
Mean (male) = ![\frac{sum of x}{n} =\frac{1020}{16} =63.75](https://tex.z-dn.net/?f=%5Cfrac%7Bsum%20of%20x%7D%7Bn%7D%20%3D%5Cfrac%7B1020%7D%7B16%7D%20%3D63.75)
Mean (female) = ![\frac{sum of y}{n} = \frac{1214}{16} = 75.875](https://tex.z-dn.net/?f=%5Cfrac%7Bsum%20of%20y%7D%7Bn%7D%20%3D%20%5Cfrac%7B1214%7D%7B16%7D%20%3D%2075.875)
Standard Deviation (male) = ![\sqrt{\frac{sum(x-63.75)^2}{16-1} } =21.315](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bsum%28x-63.75%29%5E2%7D%7B16-1%7D%20%7D%20%3D21.315)
Standard Deviation (female) = ![\sqrt{\frac{sum(y-75.875)^2}{16-1} } = 21.512](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bsum%28y-75.875%29%5E2%7D%7B16-1%7D%20%7D%20%3D%2021.512)
Coefficient of Variation = ![\frac{Std dev}{mean} *100](https://tex.z-dn.net/?f=%5Cfrac%7BStd%20dev%7D%7Bmean%7D%20%2A100)
For male, CV =
%
For female, CV =
%
Comparison : Pulse rates of males has more variability than that of females since it has a greater coefficient of variation.
The scale is a representation of what the drawing is to real life. The drawing will tend to be represented by a fixed figure such as 1 cm. In this case for every cm of drawing it is a representation of 8 millimetres in real life, therefore the drawing is bigger than the object.