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lora16 [44]
3 years ago
10

I need help on this thank you​

Mathematics
2 answers:
melamori03 [73]3 years ago
6 0

Answer:

b) BE ll CG

because the angle E and G are equal

zaharov [31]3 years ago
5 0

Answer:

B. lines BE and CG have to be parallel.

Step-by-step explanation:

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serg [7]

Answer:

Area = 25 cm²

Diagonal = 10.6cm

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Which subtraction expression has the difference 1 + 4
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4-1 would <span>have the difference of 1 + 4</span>
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Lara is putting lace trim around the border of a circular tablecloth. The tablecloth has a diameter of 1.2 meters. What is the l
mylen [45]

Answer:

3.8m

Step-by-step explanation:

Since Lara is putting lace trim around the border of a circular tablecloth, by the time she finishes she has covered the circumference.

The circumference of a circle is calculated using:

C=\pi \: d

where d is the diameter of the circle.

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6 0
3 years ago
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

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The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

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S(t)=64+Ce^{-t/800}

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and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

7 0
3 years ago
5x-2y=30 complete the missing value in the solution to the question (8, )
natali 33 [55]

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