All categories

3 years ago

Find the surface area of the regular pyramid

Mathematics

2 answers:

dlinn [17]3 years ago

8 0

24ft^2 I think this is right :)

3241004551 [841]3 years ago

4 0

Answer:

hope it's helpful ❤❤❤❤

THANK YOU.

You might be interested in

When calculating your total purchase, you must _____.

beks73 [17]

Add up all of the prices

7 0

3 years ago

Read 2 more answers

A line is represented by the equation 2x + 3y = 15. What is another way to represent the same line, for solving Y ? Help is need

Lady bird [3.3K]

The another way to represent the same line, for solving $y$ will be: $y= 5-\frac{2}{3}x$

Explanation

Given equation of the line is: $2x+3y=15$

"Solving $y$ " means we need to get $y$ alone in left side. So, we will eliminate all other terms except $y$ from the left side.

First we will subtract 2x from both sides. So, we will get......

$2x+3y-2x=15-2x\\ \\ 3y=15-2x$

Now, we will divide both sides by 3 for getting $y$ alone. So.....

$\frac{3y}{3}= \frac{15-2x}{3}\\ \\ y= 5-\frac{2}{3}x$

Thus, the another way to represent the same line, for solving $y$ will be: $y= 5-\frac{2}{3}x$

7 0

3 years ago

Toby found a $52 wallet on tge clearance rack for 60% off. if sales tax is 6.25%, how much will he pay in total

mylen [45]

Answer: Toby will pay $34.45.

Step-by-step explanation:

I did 60% of 52 and the 6.25% of 52 and added my answers together.

7 0

2 years ago

Read 2 more answers

On Saturday Kai gave his guinea pig 80 grams of the food. The table shows the amount of each type of food he gave to the guinea

Alina [70]

Answer:A

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

Note that: 1 is subtracted because it is a probability without replacement

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

4 0

2 years ago