Answer:
Step-by-step explanation:
Distance between two points
and
is given by the formula,
Distance = ![\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
a). A(-6, -4), B(-3, -1)
Distance between A and B = ![\sqrt{(-6+3)^2+(-4+1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-6%2B3%29%5E2%2B%28-4%2B1%29%5E2%7D)
= ![\sqrt{9+9}](https://tex.z-dn.net/?f=%5Csqrt%7B9%2B9%7D)
= 3√2
= 4.2 units
b). C(3.5, 1), D(-4, 2.5)
Distance between C and D = ![\sqrt{(3.5+4)^2+(1-2.5)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%283.5%2B4%29%5E2%2B%281-2.5%29%5E2%7D)
= ![\sqrt{58.5}](https://tex.z-dn.net/?f=%5Csqrt%7B58.5%7D)
= 7.65
≈ 7.7 units
c). Distance between X(5, -5) and Y(-5, 5)
Distance = ![\sqrt{(5+5)^2+(-5-5)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%285%2B5%29%5E2%2B%28-5-5%29%5E2%7D)
= ![\sqrt{200}](https://tex.z-dn.net/?f=%5Csqrt%7B200%7D)
= 10√2
= 14.14
≈ 14.1 units
Answer:
Step-by-step explanation:
6 - 3(x + 1) = 18 ⇔ 3 - 3x = 18 ⇒ <em>x = 5</em>
y - 6 = 17 ⇒ <em>y = 23</em>
z - 3 = 4z ⇒ <em>z = - 1</em>
18 - 3(0) = 9w ⇒ <em>w = 2</em>
========================
I'm going to solve for you some another question you asked, I did not see the right answer... :)
There are two scenarios, because the expression under the module can be positive and can be negative: | 3x + 2| - 2 > 3 ⇔ | 3x + 2| > 5
<em>(1).</em> If <u><em>(3x + 2) is positive</em></u> then
3x + 2 > 5 ⇒ <em>x > 3</em>
<em>(2).</em> If <u><em>(3x + 2) is negative</em></u> then
- (3x + 2) > 5
- 3x - 2 > 5
- 3x > 7 ⇒ x < -
The final answer is <em>x < - 2.3 or x > 1</em>
Answer:
No because No one will brianliest me
Step-by-step explanation:
Answer:
I think it is 64 but not 100% sure
Hope this helps :)
Answer:20
Step-by-step explanation:
range=highest number - lowest number
range=65-40
range=20