The radius of a semicircle is 5 yards. What is the semicircle's diameter?

Mathematics

1 answer:

mart [117]3 years ago

7 0

Answer:

Diameter: 10 Yards

Step-by-step explanation:

d = 2r

d = 2 ( 5 )

d = 10

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A system of equations has definitely many solutions. If 2y-4x=6 is one of the equations, which could be the other equation?

NISA [10]

The given equation is ⇒⇒⇒ 2y - 4x = 6

∴ 2y = 4x + 6 ⇒ divide all the equation over 2

∴ y = 2x + 3 and it can be written as ⇒⇒⇒ y - 2x = 3

The last equation represents a straight line with a slope = 2 and y-intercept = 3

To construct a system of equations with definitely many solutions and the equation ( 2y-4x=6 ) is one of the equations, the other equation must have the same slope and the same y-intercept.

so, the general solution of the other equation is ⇒ a ( y - 2x ) = 3a

Where a is constant and belongs to R ( All real numbers )

The system of equations which has definitely many solutions is consisting of <u>Coincident lines.</u>

8 0

3 years ago

Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an

ss7ja [257]

The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters

Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.