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guajiro [1.7K]
2 years ago
13

Count the left-handed and right-handed spirals on the cacti in the photograph.

Mathematics
1 answer:
Digiron [165]2 years ago
8 0

Answer:

2 = 1 + 1

3 = 2 + 1

5 = 3 + 2

8 = 5 + 3

13 = 8 + 5

21 = 13 + 8.

Fibonacci numbers are found in many structures in nature.

We have just found that these cacti enclose Fibonacci numbers 13 and 21.

13 and 21

Step-by-step explanation:

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14/1 ÷ 3/8 = please show work and answer fast​
jarptica [38.1K]

Answer: 37 1/3

Step-by-step explanation:

14/1÷3/8=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

14/1 × 8/3=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

14×8/1×3 = 112/3

This fraction cannot be reduced.

The fraction

112/3

is the same as

112÷3

Convert to a mixed number using

long division so

112/3=37 1/3

Therefore:

14/1 ÷ 3/8=37 1/3

5 0
3 years ago
Simplify the following expressions.<br> (x^-8/y^11)^-2<br><br> Please
kobusy [5.1K]

Answer:

y ^22  x ^16

hope this helps

3 0
3 years ago
6 less than twice a number is at least 15. Write an inequality and solve.
Ivan

Answer:

2a-6>=15 this is because the key word at least means it can be 15 or higher but it cannot be less than 15.

Step-by-step explanation:

6 0
2 years ago
3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d
Alexxx [7]

Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

6 0
3 years ago
If 1/5 of the remaining blueberries is used to make muffins how many pounds of blueberries are left in the container
nlexa [21]

Answer:

4/5.

Step-by-step explanation:

would you mind looking at my question :)

3 0
3 years ago
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